document.write( "Question 945322: the perimeter of a rectangle is 46cm the length of the rectangle is 4cm less than twice the width. find the width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #576465 by macston(5194)![]() ![]() You can put this solution on YOUR website! L=length=2W-4; W=width; P=perimeter=2(L+W) \n" ); document.write( "P=2(L+W) Substitute for L, enter given value for P \n" ); document.write( "46 cm=2(2W-4+W) \n" ); document.write( "46 cm=2(3W-4) \n" ); document.write( "46 cm=6W-8 Add 8 to each side \n" ); document.write( "54 cm=6W Divide each side by 6 \n" ); document.write( "9 cm=W \n" ); document.write( "ANSWER Width of the rectangle is 9 cm. \n" ); document.write( "CHECK \n" ); document.write( "L=2W-4=18-4=14 cm \n" ); document.write( "P=2(L+W) \n" ); document.write( "46 cm=2(14 cm+ 9 cm) \n" ); document.write( "46 cm=2(23 cm) \n" ); document.write( "46 cm=46 cm \n" ); document.write( " \n" ); document.write( " |