document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=945246>Question 945246</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A teacher has to buy 6 snack. Snack A costs $4.75 and snack B costs $6.25. If he spends $34.50, determine the number of each type of snack bought<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #576447 by </B><A HREF=/tutors/aboutme.mpl?userid=fion6002><B>fion6002(19)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fion6002><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=576447\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the number of Snack A<BR>\n" );
document.write( "let (6-x) be the number of Snack B (since we know teacher bought 6 snacks, x of them are Snack A, then the numbers left 6-x must be for snack B)\r<BR>\n" );
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document.write( "4.75x + 6.25(6-x) = 34.50<BR>\n" );
document.write( "4.75x + 37.5 - 6.25x = 34.50<BR>\n" );
document.write( "-1.5x = -3<BR>\n" );
document.write( "1.5x = 3<BR>\n" );
document.write( "x = 2\r<BR>\n" );
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document.write( "Snack A = x = 2<BR>\n" );
document.write( "Snack B = 6-x = 6-2 = 4 \r<BR>\n" );
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document.write( "Therefore the teacher bought 2 snack A and 4 snack B </SPAN>\n" );
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