document.write( "Question 80346: Oh boy! tough one for me : (\r
\n" ); document.write( "\n" ); document.write( "One fourth of a herd of camels was seen in the forest, twice the square root of that herd had gone to the mountain slopes and 3 times 5 camels remained on the riverbank. What is the numerical measure of the herd of camels? Ugg! Please help! Thank you \n" ); document.write( "
Algebra.Com's Answer #57642 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
c/4+2sqrtc+3*5=c
\n" ); document.write( "c/4+sqrtc+15=c
\n" ); document.write( "c/4+15+2sqrtc=c
\n" ); document.write( "2sqrtc=c-c/4-15
\n" ); document.write( "2sqrtc=3c/4-15
\n" ); document.write( "2sqrtc=(3c-60)/4
\n" ); document.write( "sqrtc=(3c-60)/8
\n" ); document.write( "c=[(3c-60)/8]^2
\n" ); document.write( "c=(9c^2-360c+3600)/64
\n" ); document.write( "64c=9c^2-360c+3600
\n" ); document.write( "9c^2-360c-64c+3600=0
\n" ); document.write( "9c^2-424c+3600=0
\n" ); document.write( "using the quadratic equation we get:
\n" ); document.write( "c=(424+-sqrt[-424^2-4*9*3600])/2*9
\n" ); document.write( "c=(424+-sqrt[179,776-129,600])/18
\n" ); document.write( "c=(424+-sqrt50,176)/18
\n" ); document.write( "c=(424+-224)/18
\n" ); document.write( "c=(424+224)/18
\n" ); document.write( "c=648/18
\n" ); document.write( "c=36 size of the herd.
\n" ); document.write( "proof
\n" ); document.write( "36/4+2*sqrt36+15=36
\n" ); document.write( "9+2*6+15=36
\n" ); document.write( "9+12+15=36
\n" ); document.write( "36=36
\n" ); document.write( "this was not an easy one :) :)
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