document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=945241>Question 945241</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Okay, I really just need an equation to understand this;<BR>\n" );
document.write( "Jessica mixed 5 oz of soil containing 26% clay with 6oz of soil with 14% clay. What is the content of the mixture?\r<BR>\n" );
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document.write( "Also... Nancy mixed 10 L of cranberry juice into 13 L of apple juice, that had 50% sugar content. If the cranapple mixture is 42% sugar! what was the percent of sugar in the cranberry juice? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #576410 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=576410\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.CLAY<BR>\n" );
document.write( "5 oz of soil at 26% clay=5oz(.26)=1.3 oz clay<BR>\n" );
document.write( "6 oz of soil at 14% clay=6oz(.14)=0.84 oz clay<BR>\n" );
document.write( "We have 5 oz + 6 oz =11 oz total with 1.3+0.84=2.14 oz of clay<BR>\n" );
document.write( "(2.14 oz/11 oz)(100%)=19.5% clay<BR>\n" );
document.write( "ANSWER The combined soils are 19.5% clay<BR>\n" );
document.write( "2.FRUIT JUICE<BR>\n" );
document.write( "The 23 L is 42% sugar, so there is 0.42(23L)=9.66 sugar<BR>\n" );
document.write( "The 13L apple juice at 50% had 0.50(13L)=6.50 sugar<BR>\n" );
document.write( "So of the 9.66 sugar in the blend, 6.50 came from apple juice so<BR>\n" );
document.write( "9.66-6.50=3.16 sugar came from the 10 L of cranberry juice<BR>\n" );
document.write( "(3.16/10L)(100%)=31.6% sugar in the original cranberry juice<BR>\n" );
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