document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=945236>Question 945236</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the measures of the angles of a triangle if the measure of one side is twice the measure of a second and the third angle measures two times the second decreased by 20 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #576393 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=576393\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the measures of the angles of a triangle if the measure of one side is twice the measure of a second and the third angle measures two times the second decreased by 20<BR>\n" );
document.write( "***<BR>\n" );
document.write( "let x=2nd angle<BR>\n" );
document.write( "2x=1st angle<BR>\n" );
document.write( "2x-20=3rd angle<BR>\n" );
document.write( "..<BR>\n" );
document.write( "x+2x+2x-20=180<BR>\n" );
document.write( "5x=200<BR>\n" );
document.write( "x=40<BR>\n" );
document.write( "2x=80<BR>\n" );
document.write( "2x-20=60<BR>\n" );
document.write( "..<BR>\n" );
document.write( "measure of 2nd angle=40&#730;<BR>\n" );
document.write( "measure of 1st angle=80&#730;<BR>\n" );
document.write( "measure of 3rd angle=60&#730;<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );