document.write( "Question 945125: priiscilla is 4 times older than sam. in 4 years she will be twice as old as sam. how old are they now? \n" ); document.write( "
Algebra.Com's Answer #576383 by macston(5194)![]() ![]() You can put this solution on YOUR website! S=Sam's age; P=Priscilla's age=4S \n" ); document.write( "P+4=2(S+4) Substitute for P \n" ); document.write( "4S+4=2(S+4) \n" ); document.write( "4S+4=2S+8 Subtract 4 from each side \n" ); document.write( "4S=2S+4 Subtract 2S from each side \n" ); document.write( "2S=4 Divide easch side by 2 \n" ); document.write( "S=2 ANSWER Sam is 2 years old \n" ); document.write( "P=4S=8 ANSWER Priscilla is 8 years old \n" ); document.write( "CHECK \n" ); document.write( "In 4 years, Priscilla will be twice Sam's age \n" ); document.write( "P+4=2(S+4) \n" ); document.write( "8+4=2(2+4) \n" ); document.write( "12=2(6) \n" ); document.write( "12=12 \n" ); document.write( " |