document.write( "Question 80314: Two cars leave at noon from the same point, one traveling east at 50 mph, the other traveling due north at 60 mph.
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document.write( "(a) How far apart are they at 1 PM? at 1:30 PM?
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document.write( "(b) If t is the number of hours after noon, find an equation expressing the distance between the cars as a function of t. \n" );
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Algebra.Com's Answer #57635 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! (50T)^2+(60T)^2=DISTANCE ^2 \n" ); document.write( "@ 1:00 THEY ARE \n" ); document.write( "(50*1)^2+(60*1)^2=D^2 \n" ); document.write( "5062=60^2=D62 \n" ); document.write( "2500+3600=D^2 \n" ); document.write( "D^2=5100 \n" ); document.write( "D=SQRT5100 \n" ); document.write( "D=71.414 MILES APART @ 1:00. \n" ); document.write( "------------------------------------ \n" ); document.write( "@ 1:30 THEY WILL BE: \n" ); document.write( "(50*1.5)^2+(60*1.5)^2=D^2 \n" ); document.write( "75^2+90^2=D^2 \n" ); document.write( "D^2=5625+8100 \n" ); document.write( "D^2=13725 \n" ); document.write( "D=117.154 MILES APART @ 1:30. \n" ); document.write( "------------------------------------------------------------ \n" ); document.write( "FORMULA IN TERMS OF T IS: \n" ); document.write( "(S1T)^2+(S2T)^2=D^2 \n" ); document.write( "T^2(S1^2+S2^2)=D^2 \n" ); document.write( "T^2=D^2/(S1^2+S2^2) \n" ); document.write( "T=(D/SQRT(S1^2+S2^2) \n" ); document.write( " \n" ); document.write( " |