document.write( "Question 945169: Please help me with this one too. :)\r
\n" ); document.write( "\n" ); document.write( "An electronics company used a pipe that was 100 ft long and had a radius of 10 ft. Inside the pipe was a smaller cylindrical tube, for wires, that had a radius of 2 ft and was as long as the pipe. The remaining space in the pipe, outside the tube, was filled with liquid foam.
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\n" ); document.write( "What was the volume of the foam inside the pipe? Use 3.14 to approximate pi.
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Algebra.Com's Answer #576334 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
Let R=large radius, S= small radius, L=length
\n" ); document.write( "Volume (large)=\"V=pi%28R%5E2%29%2AL\"
\n" ); document.write( "Volume (small)=\"V=pi%28S%5E2%29%2AL\"
\n" ); document.write( "Volume (foam)= Volume (large) - Volume (small)
\n" ); document.write( "\"Volume+%28foam%29=%28pi%28R%5E2%29%2AL%29-%28pi%28S%5E2%29%2AL%29\" factor out pi(L)
\n" ); document.write( "\"Volume+%28foam%29=pi%28L%29%28R%5E2-S%5E2%29\" Enter values
\n" ); document.write( "\"Volume+%28foam%29=pi%28100+ft%29%2810%5E2-2%5E2%29\"
\n" ); document.write( "\"Volume+%28foam%29=pi%28100+ft%29%28100-4%29\"
\n" ); document.write( "\"Volume+%28foam%29=pi%28100ft%29%2896+sq+ft%29\"
\n" ); document.write( "\"Volume+%28foam%29=%289600+cu+ft%29pi\"=(9600 cu ft)(3.14)=30144 cu ft
\n" ); document.write( "ANSWER Volume of foam is 30144 cubic feet.
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