document.write( "Question 945169: Please help me with this one too. :)\r
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document.write( "An electronics company used a pipe that was 100 ft long and had a radius of 10 ft. Inside the pipe was a smaller cylindrical tube, for wires, that had a radius of 2 ft and was as long as the pipe. The remaining space in the pipe, outside the tube, was filled with liquid foam.
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document.write( "What was the volume of the foam inside the pipe? Use 3.14 to approximate pi. \n" );
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Algebra.Com's Answer #576334 by macston(5194)![]() ![]() You can put this solution on YOUR website! Let R=large radius, S= small radius, L=length \n" ); document.write( "Volume (large)= \n" ); document.write( "Volume (small)= \n" ); document.write( "Volume (foam)= Volume (large) - Volume (small) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWER Volume of foam is 30144 cubic feet. \n" ); document.write( " |