document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=945148>Question 945148</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two trains are 440 miles apart, and their speeds differ by 16 mph. Find the speed of each train if they are traveling toward each other and will meet in 4 hours. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #576315 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=576315\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let S=the speed of the slower train , S+16mph the speed of the faster train<BR>\n" );
document.write( "The combined speed of the trains must be 440 mi/4hrs=110 mph<BR>\n" );
document.write( "S+(S+16)=110 mph<BR>\n" );
document.write( "2S+16=110mph subtract 16 from each side<BR>\n" );
document.write( "2S=94 mph Divide each side by 2<BR>\n" );
document.write( "S=47 mph ANSWER The slower train is traveling 47 mph<BR>\n" );
document.write( "S+16=63mph ANSWER the faster train is traveling 63 mph<BR>\n" );
document.write( "CHECK<BR>\n" );
document.write( "In four hours, the slower train travels (4 hrs)(47 mph)= 188 miles<BR>\n" );
document.write( "In four hours, the faster train travels (4 hrs)(63 mph)= 252 miles<BR>\n" );
document.write( "188 miles + 252 miles=440 miles, which is the distance that separates them. </SPAN>\n" );
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