document.write( "Question 945142: Solve the system using substitution.
\n" ); document.write( "
\n" ); document.write( "y = 2x + 7
\n" ); document.write( "y = 5x + 4
\n" ); document.write( "

Algebra.Com's Answer #576312 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"y+=+2x+%2B+7\"......eq.1
\n" ); document.write( "\"y+=+5x+%2B+4\"......eq.2
\n" ); document.write( "-----------------------------substitute \"5x+%2B+4\" for \"y\" in eq.1\r
\n" ); document.write( "\n" ); document.write( "\"5x+%2B+4+=+2x+%2B+7\"......eq.1...solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"5x-2x+=+7-4\"\r
\n" ); document.write( "\n" ); document.write( "\"3x+=+3\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+3%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x+=+1%29\"\r
\n" ); document.write( "\n" ); document.write( "go to \"y+=+5x+%2B+4\"......eq.2 substitute \"1\" for \"x\" and solve for \"y\"\r
\n" ); document.write( "\n" ); document.write( " \"y+=+5%2A1+%2B+4\"\r
\n" ); document.write( "\n" ); document.write( " \"highlight%28y+=+9%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );