document.write( "Question 944970: I am not sure how to work this out. I would appreciate any help. Thanks!\r
\n" ); document.write( "\n" ); document.write( "Let \"c\" be a number and consider the function f(x) = { ax^2 -5, if x <1
\n" ); document.write( " c, if x =1
\n" ); document.write( " (1/x)-2a, if x > 1 }\r
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\n" ); document.write( "\n" ); document.write( "a) Find all numbers for \"a\" such that lim x-> 1 f(x) exists\r
\n" ); document.write( "\n" ); document.write( "b) Is there a number \"c\" such that f(x) is continuous at x=1?
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Algebra.Com's Answer #576294 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
For the limit to exist, \"f%28x%29\" as you approach from the left (\"x%3C1\") must equal \"f%28x%29\" as you approach from the right \"x%3E=1\".
\n" ); document.write( "\"ax%5E2-5=1%2Fx-2a\"
\n" ); document.write( "\"a%281%29%5E2-5=1%2F1-2a\"
\n" ); document.write( "\"a-5=1-2a\"
\n" ); document.write( "\"3a=6\"
\n" ); document.write( "\"a=2\"
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\n" ); document.write( "For it to be continuous then,
\n" ); document.write( "\"c=2\"
\n" ); document.write( "That way the limit from the left, the limit from the right and the value at x=1 are all the same which is the definition of continuous.\r
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