document.write( "Question 944970: I am not sure how to work this out. I would appreciate any help. Thanks!\r
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document.write( "Let \"c\" be a number and consider the function f(x) = { ax^2 -5, if x <1
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document.write( " c, if x =1
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document.write( " (1/x)-2a, if x > 1 }\r
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document.write( "a) Find all numbers for \"a\" such that lim x-> 1 f(x) exists\r
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document.write( "b) Is there a number \"c\" such that f(x) is continuous at x=1?
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Algebra.Com's Answer #576294 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! For the limit to exist, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "For it to be continuous then, \n" ); document.write( " \n" ); document.write( "That way the limit from the left, the limit from the right and the value at x=1 are all the same which is the definition of continuous.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |