document.write( "Question 944933: help me solve this problem please,\r
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document.write( "Suppose you work in a lab, and you need a 33% acid solution. You have a 5% solution and a 40% solution in stock. You need 10 liters of the 33% acid solution. how many liters of 5% solution and 40% solution should you use? \n" );
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Algebra.Com's Answer #576249 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Suppose you work in a lab, and you need a 33% acid solution. \n" ); document.write( " You have a 5% solution and a 40% solution in stock. \n" ); document.write( " You need 10 liters of the 33% acid solution. \n" ); document.write( " how many liters of 5% solution and 40% solution should you use? \n" ); document.write( ": \n" ); document.write( "let a = amt of 40% solution \n" ); document.write( "the resulting amt is to be 10 liters, therefore \n" ); document.write( "(10-a) = amt of 5% solution \n" ); document.write( ": \n" ); document.write( "A typical mixture equation \n" ); document.write( "40a + 5(10-a) = 33(10) \n" ); document.write( "40a + 50 - 5a = 330 \n" ); document.write( "40a - 5a = 330 - 50 \n" ); document.write( "35a = 280 \n" ); document.write( "a = 280/35 \n" ); document.write( "a = 8 liters of the 40% solution \n" ); document.write( "then \n" ); document.write( "10 - 8 = 2 liters of the 5% solution \n" ); document.write( " |