document.write( "Question 945014: Phyllis can rake our lawn in 50 minutes and I can do it in 40 minutes. If she rakes for five minutes before I join her, how long will take for us to finish? \n" ); document.write( "
Algebra.Com's Answer #576232 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Phyllis can rake our lawn in 50 minutes and I can do it in 40 minutes. If she rakes for five minutes before I join her, how long will take for us to finish? \n" ); document.write( "----- \n" ); document.write( "General idea: rate*time = work done \n" ); document.write( "---------- \n" ); document.write( "Phyllis's rate:: 1/50 job/min \n" ); document.write( "My rate:: 1/40 job/min \n" ); document.write( "------- \n" ); document.write( "Equation: \n" ); document.write( "work + work = work done \n" ); document.write( "(1/50)*5 + (1/40)x = 1 \n" ); document.write( "40*5 + 50x = 40*50 \n" ); document.write( "---- \n" ); document.write( "200 + 50x = 2000 \n" ); document.write( "50x = 1850 \n" ); document.write( "x = 37 minutes (time for me to finish the job) \n" ); document.write( "----------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------------ \n" ); document.write( " |