document.write( "Question 945014: Phyllis can rake our lawn in 50 minutes and I can do it in 40 minutes. If she rakes for five minutes before I join her, how long will take for us to finish? \n" ); document.write( "
Algebra.Com's Answer #576232 by stanbon(75887)\"\" \"About 
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Phyllis can rake our lawn in 50 minutes and I can do it in 40 minutes. If she rakes for five minutes before I join her, how long will take for us to finish?
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\n" ); document.write( "General idea: rate*time = work done
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\n" ); document.write( "Phyllis's rate:: 1/50 job/min
\n" ); document.write( "My rate:: 1/40 job/min
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\n" ); document.write( "Equation:
\n" ); document.write( "work + work = work done
\n" ); document.write( "(1/50)*5 + (1/40)x = 1
\n" ); document.write( "40*5 + 50x = 40*50
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\n" ); document.write( "200 + 50x = 2000
\n" ); document.write( "50x = 1850
\n" ); document.write( "x = 37 minutes (time for me to finish the job)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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