document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=945012>Question 945012</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangular backyard is 6 more than the width of the backyard. The perimeter of the backyard is 56 feet. What is the area of the backyard? (How would I work this out?) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #576231 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=576231\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Width=W:Length=L=W+6 Perimeter=P=56 feet<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "56 feet=2(L+W) Substitute for L<BR>\n" );
document.write( "56 feet=2(W+6+W)<BR>\n" );
document.write( "56 feet=2(2W+6)<BR>\n" );
document.write( "56 feet=4W+12 Subtract 12 from each side<BR>\n" );
document.write( "44 feet=4W Divide each side by 4<BR>\n" );
document.write( "11 feet=W ANSWER 1: Width is 11 feet.<BR>\n" );
document.write( "L=W+6=11+6=17 feet ANSWER 2: Length is 17 feet.<BR>\n" );
document.write( "Area=L*W=(17 feet)(11 feet)=187 sq ft<BR>\n" );
document.write( "ANSWER The area of the back yard is 187 sq ft<BR>\n" );
document.write( "CHECK<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "56 feet=2(17 feet+11 feet)<BR>\n" );
document.write( "56 feet=2(28 feet)<BR>\n" );
document.write( "56 feet=56 feet </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );