document.write( "Question 944959: Two angles are supplementary. The measure of one angle is 5 greater than 40% of the other. Find the measures of both angles. \n" ); document.write( "
Algebra.Com's Answer #576204 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "Two angles \"alpha\" and \"beta\" are supplementary and it means they add up to \"180\"°.\r
\n" ); document.write( "\n" ); document.write( "so, \"alpha%2Bbeta=180\" .........eq.1\r
\n" ); document.write( "\n" ); document.write( "if the measure of one angle (let’s say \"alpha\") is \"5\" greater than \"40\"% of the other \"beta\", then we have\r
\n" ); document.write( "\n" ); document.write( " \"alpha=%2840%2F100%29beta%2B5\"....eq.2 .......substitute in eq.1\r
\n" ); document.write( "\n" ); document.write( "\"%2840%2F100%29beta%2B5%2Bbeta=180\" ....solve for \"beta\"\r
\n" ); document.write( "\n" ); document.write( "\"0.40beta%2Bbeta=180-5\"\r
\n" ); document.write( "\n" ); document.write( "\"1.40beta=175\"\r
\n" ); document.write( "\n" ); document.write( "\"beta=175%2F1.40\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28beta=125%29\"°\r
\n" ); document.write( "\n" ); document.write( "then \"alpha%2B125=180\" =>\"alpha=180-125\" =>\"highlight%28alpha=55%29\"° \r
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