document.write( "Question 944910: It took Henri 50 h of cycling to finish his bike tour. On the return trip over the same route, he increased his cycling rate by 1 mi/h and took 45 h. What was his rate on the return trip. \n" ); document.write( "

Algebra.Com's Answer #576170 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+r+\"$ = his rate on the cycling tour
\n" ); document.write( "Let $\"+d+\"$ = distance of the cycling tour in miles
\n" ); document.write( "------------------
\n" ); document.write( "Equation for the tour:
\n" ); document.write( " $\"+d+=+r%2A50+\"$
\n" ); document.write( "Equation for return trip:
\n" ); document.write( " $\"+d+=+%28+r+%2B+1+%29%2A45+\"$
\n" ); document.write( "--------------------
\n" ); document.write( "By substitution:
\n" ); document.write( " $\"+50r+=+45r+%2B+45+\"$
\n" ); document.write( " $\"+5r+=+45+\"$
\n" ); document.write( " $\"+r+=+9+\"$
\n" ); document.write( " $\"+r+%2B+1+=+10+\"$
\n" ); document.write( "----------------
\n" ); document.write( "His rate on the return trip was 10 mi/hr
\n" ); document.write( "check:
\n" ); document.write( " $\"+d+=+r%2A50+\"$
\n" ); document.write( " $\"+d+=+9%2A50+\"$
\n" ); document.write( " $\"+d+=+450+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+d+=+%28+r+%2B+1+%29%2A45+\"$
\n" ); document.write( " $\"+d+=+10%2A45+\"$
\n" ); document.write( " $\"+d+=+450+\"$
\n" ); document.write( "OK \n" ); document.write( "

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