document.write( "Question 944880: What values make the inequality x+6/6-x<0 true? \n" ); document.write( "

Algebra.Com's Answer #576138 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( " $\"%28x%2B6%29%2F%286-x%29+%3C+0\"$ \r
\n" ); document.write( "\n" ); document.write( "denominator cannot be zero; so, $\"%286-x%29\"$ will be $\"+0\"$ if $\"x=6\"$ \r
\n" ); document.write( "\n" ); document.write( "it means $\"x\"$ must be greater then $\"6\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"highlight%28x+%3E+6%29\"$ \r
\n" ); document.write( "\n" ); document.write( "the values of $\"x\"$ are:{ $\"7\"$ , $\"8\"$ , $\"9\"$ ,......}\r
\n" ); document.write( "\n" ); document.write( "and these values make the inequality $\"%28x%2B6%29%2F%286-x%29+%3C+0\"$ true\r
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\n" ); document.write( "\n" ); document.write( "try for $\"x=7\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"%287%2B6%29%2F%286-7%29+%3C+0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"13%2F-1+%3C+0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"-13%3C0\"$ which is true\r
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