document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=944828>Question 944828</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi! I just want to know how to transform this equation to a quadratic equation.. and Kindly please tell me how you did it. Just for my physics problem. Thanks! :D \r<BR>\n" );
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document.write( "-40 = 100t + 1/2 (-9.8)t^2<BR>\n" );
document.write( "It should come like this, right?<BR>\n" );
document.write( "-40 = 100t - 4.9t^2\r<BR>\n" );
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document.write( "But how to arrange them? thanks! :D </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #576088 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=576088\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -40 = 100t + 1/2 (-9.8)t^2<BR>\n" );
document.write( "-4.9t^2 +100t +40 = 0<BR>\n" );
document.write( "this is an equation of a parabola that opens downward<BR>\n" );
document.write( "max height in meters is determined by solving for the axis of symmetry<BR>\n" );
document.write( "t = -b/2a = -100 / (2*-4.9) = 10.204081633, therefore<BR>\n" );
document.write( "max height occurs at 10.204081633 seconds and max height is<BR>\n" );
document.write( "h(t) = -4.9(10.204081633^2) +100*(10.204081633) +40<BR>\n" );
document.write( "max height = 550.204081633 meters<BR>\n" );
document.write( " </SPAN>\n" );
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