document.write( "Question 944780: Consider the expression, \"+r%5Es+=+A%28t-p%29%5Ex+\" . An equivalent logarithmic expression is. r is the base\r
\n" ); document.write( "\n" ); document.write( "A. \"+s+=+A+log+%28+r%2C+%28t-p%29%29%5Ex+\"
\n" ); document.write( "B. \"+s+=+log+%28+r%2C+Ax+%28t-p%29%29+\"
\n" ); document.write( "C. \"+s+=+Ax+log+%28+r%2C+%28t-p%29%29+\"
\n" ); document.write( "D. \"+s+=+log+%28+r%2C+A%29%28t-p%29%5Ex+\"\r
\n" ); document.write( "\n" ); document.write( "Struggling with this question, can someone show me the steps used to solve this question.\r
\n" ); document.write( "\n" ); document.write( "Thank you
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Algebra.Com's Answer #576055 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"X+=+B%5EY\" is equivalent to \"Y+=+log%28B%2C+X%29\"\r
\n" ); document.write( "\n" ); document.write( "you are given \"+r%5Es+=+A%28t-p%29%5Ex+\"\r
\n" ); document.write( "\n" ); document.write( "compare it to \"X+=+B%5EY\"\r
\n" ); document.write( "\n" ); document.write( "if \"r\" is base then \"Y=s\" and \"X++=A%28t-p%29%5Ex\" and \"Y+=+log%28B%2C+X%29\" will be\r
\n" ); document.write( "\n" ); document.write( "\"s=log%28r%2CA%28t-p%29%5Ex%29%29\"\r
\n" ); document.write( "\n" ); document.write( "so, answer is D. \"+s+=+log+%28+r%2C+A%28t-p%29%5Ex+%29\"
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