document.write( "Question 944788: Good morning,
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document.write( "Please help me solve this equation.\r
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document.write( "solve algebraically using only one variable: find three consecutive odd integers such three times the sum of the second and third integer is two less than twice the first integer.\r
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document.write( "Thank you!\r
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document.write( "Best,
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document.write( "SM \n" );
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Algebra.Com's Answer #576053 by macston(5194) You can put this solution on YOUR website! First integer is I, Second is I+2, Third is I+4 \n" ); document.write( "Three times the sum of the second and third integer is two less than twice the first integer. \n" ); document.write( "3((I+2)+(I+4))+2=2I \n" ); document.write( "3(I+2+I+4)+2=2I \n" ); document.write( "3(2I+6)+2=2I \n" ); document.write( "6I+18+2=2I \n" ); document.write( "6I+20=2I Subtract 2I from each side \n" ); document.write( "4I+20=0 Subtract 20 from each side \n" ); document.write( "4I=-20 Divide each side by 4 \n" ); document.write( "I=-5 ANSWER 1: First digit is -5 \n" ); document.write( "I+2=-5+2=-3 ANSWER 2: Second digit is -3 \n" ); document.write( "I+4=-5+4=-1 ANSWER 3: Third digit is -1 \n" ); document.write( "CHECK \n" ); document.write( "3*(-3+(-1))=2*(-5)-2 \n" ); document.write( "3*(-4)=(-10)-2 \n" ); document.write( "(-12)=(-12)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |