document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=944587>Question 944587</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can somebody help  me solve these equation using substitution ? thanks\r<BR>\n" );
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document.write( "1. {3x+4y=-2<BR>\n" );
document.write( "{x=6y-8 \r<BR>\n" );
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document.write( "2. {2x+y=-10<BR>\n" );
document.write( "{x=-2y-2 \r<BR>\n" );
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document.write( "can someone help me please. thank you SHOW all work please!!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #575994 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=575994\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. <BR>\n" );
document.write( "3x + 4y =-2<BR>\n" );
document.write( "x = 6y - 8<BR>\n" );
document.write( "We know that x = (6y-8) so substitute x with this in the 1st equation<BR>\n" );
document.write( "3(6y-8) + 4y = -2<BR>\n" );
document.write( "distribute<BR>\n" );
document.write( "18y - 24 + 4y = -2<BR>\n" );
document.write( "Combine like terms<BR>\n" );
document.write( "18y + 4y = -2 + 24<BR>\n" );
document.write( "22y = 22<BR>\n" );
document.write( "divide both sides by 22<BR>\n" );
document.write( "y = 1<BR>\n" );
document.write( "find x using the 2nd equation; x = 6y - 8; replace y with 1<BR>\n" );
document.write( "x = 6(1) - 8<BR>\n" );
document.write( "x = 6 - 8<BR>\n" );
document.write( "x = -2<BR>\n" );
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document.write( "Check your solutions in the 1st equation; 3x + 4y = -2, replace x and y<BR>\n" );
document.write( "3(-2) + 4(1) = -2<BR>\n" );
document.write( "-6 + 4 = -2, confirms our answers<BR>\n" );
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document.write( "2. <BR>\n" );
document.write( "2x + y = -10<BR>\n" );
document.write( "x = -2y - 2<BR>\n" );
document.write( "Substitute (-2y-2) for x in the 1st equation<BR>\n" );
document.write( "2(-2y-2) + y = -10<BR>\n" );
document.write( "-4y - 4 + y = -10<BR>\n" );
document.write( "-4y + y = -10 + 4<BR>\n" );
document.write( "-3y = -6<BR>\n" );
document.write( "y has to be positive, multiply both sides by -1 <BR>\n" );
document.write( "3y = 6<BR>\n" );
document.write( "divide both sides by 3<BR>\n" );
document.write( "y = 6/3<BR>\n" );
document.write( " y = 2<BR>\n" );
document.write( "find x using the 2nd equation x = -2y - 2, replace y with 2<BR>\n" );
document.write( "x = -2(2) - 2<BR>\n" );
document.write( "x = -4 - 2<BR>\n" );
document.write( "x = -6<BR>\n" );
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document.write( "Check this in the 1st equation, replace x & y in 2x + y = -10<BR>\n" );
document.write( "2(-6) + 2 = -10<BR>\n" );
document.write( "-12 + 2 = -10,confirms our answers<BR>\n" );
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document.write( "Was this step-by-step enough? ankor@att.net<BR>\n" );
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