document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=944601>Question 944601</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the ratio of the length to the width of a rectangle is 2:3. if the perimeter of the rectangle is 120, find the dimensions </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #575938 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=575938\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the ratio of the length to the width of a rectangle is 2:3. if the perimeter of the rectangle is 120, find the dimensions<BR>\n" );
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document.write( "Note:: 2:3 is the same as 2x to 3x where 2x is length and 3x is width.<BR>\n" );
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document.write( "Perimeter = 2(length + width)<BR>\n" );
document.write( "120 = 2(2x+3x)<BR>\n" );
document.write( "60 = 5x<BR>\n" );
document.write( "x = 12<BR>\n" );
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document.write( "2x = 2*12 = 24 (length)<BR>\n" );
document.write( "3x = 3*12 = 36 (width)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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