document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=80277>Question 80277</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help I have been trying to figure this problem out but am unable to even get started\r<BR>\n" );
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document.write( "-9x+2y=2<BR>\n" );
document.write( "+6x+8y=-6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #57592 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=57592\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -9x+2y=2<BR>\n" );
document.write( "+6x+8y=-6<BR>\n" );
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document.write( "Plan to get rid of the y terms so you can solve for \"x\".<BR>\n" );
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document.write( "Multiply the 1st equation by 4 to get:<BR>\n" );
document.write( "-36x+8y=8<BR>\n" );
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document.write( "Subtract that from the 2nd equation to get:<BR>\n" );
document.write( "42x=-14<BR>\n" );
document.write( "x=-1/3<BR>\n" );
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document.write( "Substitute that back into one of the earlier equations to solve for \"y\".<BR>\n" );
document.write( "6x+8y=-6<BR>\n" );
document.write( "6*(-1/3)+8y=-6<BR>\n" );
document.write( "-2 + 8y = -6<BR>\n" );
document.write( "8y = -4<BR>\n" );
document.write( "y=-1/2<BR>\n" );
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document.write( "Solution x=-1/3 ; y=-1/2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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