document.write( "Question 944527: Two rental car companies are running specials this month. At Gavin's Rentals, customers will pay $56 to rent a mid-sized car for the first day, plus $3 for each additional day. At Wildgrove Rent-a-Car, the price for a mid-sized car is $53 for the first day and $6 for every additional day beyond that. At some point, renting from either one of the companies would cost a customer the same amount. How many additional days would that take? How much would the customer pay?
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Algebra.Com's Answer #575915 by macston(5194) You can put this solution on YOUR website! Gavin's cost=$56+$3d where d is additional days \n" ); document.write( "Wildgrove cost=$53+$6d where d is additional days \n" ); document.write( "On what day would both be the same? \n" ); document.write( "$56+$3d=$53+$6d Subtract $53 from each side \n" ); document.write( "$3+$3d=$6d Subtract $3d from each side \n" ); document.write( "$3=$3d Divide each side by $3 \n" ); document.write( "1=d :ANSWER On the first additional day, both companies charge $59 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |