document.write( "Question 944490: Find two consecutive odd integers such that when the smaller is doubled, the results is 7 more than the larger integer. \n" ); document.write( "
Algebra.Com's Answer #575882 by macston(5194) You can put this solution on YOUR website! S=smaller integer; L=larger integer=S+2 \n" ); document.write( "2S=L+7 Substitute for L \n" ); document.write( "2S=(S+2)+7 \n" ); document.write( "2S=S+9 Subtract S from each side \n" ); document.write( "S=9 ANSWER 1 Smaller Number is 9 \n" ); document.write( "L=S+2=9+2=11 ANSWER 2 Larger number is 11 \n" ); document.write( "CHECK: \n" ); document.write( "Double the smaller is 7 more than the larger. \n" ); document.write( "2S=L+7 \n" ); document.write( "2(9)=(11)+7 \n" ); document.write( "18=18 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |