document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=944404>Question 944404</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a chemist has two alcohol-in-water: a 20% alcohol solution and a 50% alcohol solution. He needs 12 L of a solution that is 45% alcohol. How many liters of the two starting solutions should he mix </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #575859 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=575859\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a chemist has two alcohol-in-water: a 20% alcohol solution and a 50% alcohol solution. He needs 12 L of a solution that is 45% alcohol. How many liters of the two starting solutions should he mix<BR>\n" );
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document.write( "let x=amt of 20% solution to mix<BR>\n" );
document.write( "12-x=amt of 50% solution to mix<BR>\n" );
document.write( "20%x+50%(12-x)=45%*12<BR>\n" );
document.write( ".20x+6-.50x=5.4<BR>\n" );
document.write( ".30x=.60<BR>\n" );
document.write( "x=2<BR>\n" );
document.write( "12-x=10<BR>\n" );
document.write( "amt of 20% solution to mix=2 liters<BR>\n" );
document.write( "amt of 50% solution to mix=10 liters </SPAN>\n" );
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