document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=944398>Question 944398</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the pressure exerted by a certain liquid at a given point varies directly as the depth of the point beneath the surface of the liquid.  The pressure at 50 feet is 27 pounds per square inch.  What is the pressure at 190 feet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #575814 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=575814\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the pressure exerted by a certain liquid at a given point varies directly as the depth of the point beneath the surface of the liquid. The pressure at 50 feet is 27 pounds per square inch. What is the pressure at 190 feet?<BR>\n" );
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document.write( "p =kd<BR>\n" );
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document.write( "solve for \"k\" using \"p is 27 at a depth of 50 ft\"::<BR>\n" );
document.write( "27 = k*50<BR>\n" );
document.write( "k = 0.54<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "p = 0.54d<BR>\n" );
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document.write( "Ans:: p - 0.54*190 = 102.6 ppi<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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