document.write( "Question 944304: find three consecutive odd integers such that 4 times the sum of the last two is 2 greater than 10 times the first. \n" ); document.write( "
Algebra.Com's Answer #575769 by macston(5194)\"\" \"About 
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Let F,S, and T be first, second and third odd integers
\n" ); document.write( "S=F+2, T=F+4
\n" ); document.write( "10F+2=4(S+T)
\n" ); document.write( "10F+2=4S+4T Substitute for S and T, solve for F
\n" ); document.write( "10F+2=4(F+2)+4(F+4)
\n" ); document.write( "10F+2=4F+8+4F+16 Subtract 8F from each side
\n" ); document.write( "2F+2=24 Subtract 2 from each side
\n" ); document.write( "2F=22
\n" ); document.write( "F=11 ANSWER First integer is 11
\n" ); document.write( "S=F+2=13 ANSWER Second integer is 13
\n" ); document.write( "T=F+4=15 ANSWER Third integer is 15
\n" ); document.write( "CHECK
\n" ); document.write( "10F+2=4(S+T)
\n" ); document.write( "10(11)+2=4(13+15)
\n" ); document.write( "110+2=4(28)
\n" ); document.write( "112=112
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