document.write( "Question 80251: log 4x= log 5+log(x+1) \n" ); document.write( "

Algebra.Com's Answer #57574 by tutor_paul(519) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"log+4x=+log+5%2Blog%28%28x%2B1%29%29\"$
\n" ); document.write( "First, get the x terms alone on one side of the equation:
\n" ); document.write( " $\"log4x-log%28%28x%2B1%29%29=log5\"$
\n" ); document.write( "You can use a log property to rewrite the left hand side:
\n" ); document.write( " $\"log%28%284x%2F%28%28x%2B1%29%29%29%29=log5\"$
\n" ); document.write( "Now you can raise 10 to each side of the equation, effectively cancelling out the logs:
\n" ); document.write( " $\"4x%2F%28x%2B1%29=5\"$
\n" ); document.write( "solve for x:
\n" ); document.write( " $\"4x=5x%2B5\"$
\n" ); document.write( " $\"highlight%28x=-5%29\"$
\n" ); document.write( "Good Luck,
\n" ); document.write( "tutor_paul@yahoo.com \n" ); document.write( "

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