document.write( "Question 944267: Two cars leave towns 600 kilometers apart at the same time and travel toward each other. One cars rate is 14 kilometers per hour more than the other's. If they meet in 3 hours, what is the rate of the fastest car? \n" ); document.write( "
Algebra.Com's Answer #575719 by TimothyLamb(4379)\"\" \"About 
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x = speed of slow car (kph)
\n" ); document.write( "y = speed of fast car (kph)
\n" ); document.write( "y = x + 14
\n" ); document.write( "---
\n" ); document.write( "s = d/t
\n" ); document.write( "t = d/s
\n" ); document.write( "---
\n" ); document.write( "speed of cars relative to each other:
\n" ); document.write( "s = x + y
\n" ); document.write( "s = x + x + 14
\n" ); document.write( "s = 2x + 14
\n" ); document.write( "---
\n" ); document.write( "s = 600/3
\n" ); document.write( "---
\n" ); document.write( "equate s's:
\n" ); document.write( "2x + 14 = 600/3
\n" ); document.write( "2x = 600/3 - 14
\n" ); document.write( "x = (600/3 - 14)/2
\n" ); document.write( "(600/3 - 14)/2
\n" ); document.write( "---
\n" ); document.write( "copy and paste the above expression in to this calculator:
\n" ); document.write( "http://sooeet.com/math/scientific-calculator.php
\n" ); document.write( "---
\n" ); document.write( "x = 93
\n" ); document.write( "y = x + 14
\n" ); document.write( "y = 93 + 14
\n" ); document.write( "y = 107
\n" ); document.write( "---
\n" ); document.write( "answer:
\n" ); document.write( "y = speed of fast car (kph) = 107
\n" ); document.write( "---
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