document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=944172>Question 944172</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a square is 64 meters. If the field is surrounded by a running path of width 3.5 meters, find the area of the path. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #575694 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=575694\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sides of square with perimeter=64 m=4(S)=16. Each side of the field is 16 m<BR>\n" );
document.write( "The running path adds 3.5 m to each end of the side, making entire area of field and running path 23 meters by 23 meters.  Area of this square (field and path)is 23x23=529 sq meters.  Area of the field only is 16 m x 16 m=256 sq meters.<BR>\n" );
document.write( "Area of path and field - area of field = area of path<BR>\n" );
document.write( "529 sq meters - 256 sq meters = 273 sq meters ANSWER Area of the path is 273 sq m. </SPAN>\n" );
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