document.write( "Question 944156: whats the VA and HA of this problem? And how is it graphed?\r
\n" ); document.write( "\n" ); document.write( "4x^2/x^2+1 \n" ); document.write( "
Algebra.Com's Answer #575667 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
to find the vertical asymptote, look for the value of x that makes the denominator equal to 0.
\n" ); document.write( "since there is no value of x that will make the denominator equal to 0, you don't have a vertical asymptote.
\n" ); document.write( "the trick to finding the horizontal asymptote is to divide both numerator and denominator by the value of x that has the highest exponent.
\n" ); document.write( "in your problem, that would be x^2.
\n" ); document.write( "your equation becomes:
\n" ); document.write( "4x^2 / 4x^2 divided by (x^2 + 1) / x^2 which becomes:
\n" ); document.write( "4x^2 / x^2 divided by x^2 / x^2 + 1 / x^2
\n" ); document.write( "simplify this expression to get:
\n" ); document.write( "4 / 1 divided by 1 + 1 / x^2
\n" ); document.write( "as x approaches infinity, 1 / x^2 approaches 0, so the expression becomes:
\n" ); document.write( "4 / 1 divided by 1 which is equal to 4.
\n" ); document.write( "your horizontal asymptote is equal to 4.
\n" ); document.write( "summary:
\n" ); document.write( "you do not have a vertical asymptote.
\n" ); document.write( "your horizontal asymptote is equal to 4.
\n" ); document.write( "here's a graph of your equation.
\n" ); document.write( "\"$$$\"
\n" ); document.write( "here's a link to information about vertical and horizontal asymptotes.
\n" ); document.write( "http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut40_ratgraph.htm
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