document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=944105>Question 944105</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I tried to use similar problems but can't seem to figure this one out. Please provide step by step so I can understand for future :)\r<BR>\n" );
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document.write( "FInd a 6digit # in which the 1st digit is 1 more than the 3rd, the 2nd digit is 1 less than the 4th, the 5th digit is 1 less than the 3rd, and the 6th digit is 1 more than the 4th.  The sum of the 2nd and 3rd digit equals the 1st.  The sum of all digits is 30.  \r<BR>\n" );
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document.write( "adrianna.email@gmail.com    thanks  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #575646 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=575646\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Probably a lot of ways to do this, Write an equation for each statement<BR>\n" );
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document.write( "FInd a 6digit # <BR>\n" );
document.write( "let the six digits be: a, b, c, d, e, f<BR>\n" );
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document.write( "in which the 1st digit is 1 more than the 3rd,<BR>\n" );
document.write( "a = c + 1<BR>\n" );
document.write( "or<BR>\n" );
document.write( "c = a - 1<BR>\n" );
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document.write( "the 2nd digit is 1 less than the 4th,<BR>\n" );
document.write( "b = d - 1<BR>\n" );
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document.write( " the 5th digit is 1 less than the 3rd,<BR>\n" );
document.write( "e = c - 1<BR>\n" );
document.write( "replace c with (a-1)<BR>\n" );
document.write( "e = a - 1 - 1<BR>\n" );
document.write( "e = a - 2<BR>\n" );
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document.write( " and the 6th digit is 1 more than the 4th.<BR>\n" );
document.write( "f = d + 1<BR>\n" );
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document.write( " The sum of the 2nd and 3rd digit equals the 1st.<BR>\n" );
document.write( "b + c = a<BR>\n" );
document.write( "replace b with (d-1)<BR>\n" );
document.write( "d - 1 + c = a<BR>\n" );
document.write( "replace c with (a-1)<BR>\n" );
document.write( "d - 1 + a - 1 = a<BR>\n" );
document.write( "d - 2 = a - a<BR>\n" );
document.write( "d = 2<BR>\n" );
document.write( "then we know f = d + 1, therefore<BR>\n" );
document.write( "f = 2 + 1<BR>\n" );
document.write( "f = 3<BR>\n" );
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document.write( " The sum of all digits is 30. <BR>\n" );
document.write( "a + b + c + d + e + f = 30<BR>\n" );
document.write( "replace b+c with a and d with 2, replace f with 3<BR>\n" );
document.write( "a + a + 2 + e + 3 = 30<BR>\n" );
document.write( "2a + e = 30 - 2 = 3<BR>\n" );
document.write( "2a + e = 25<BR>\n" );
document.write( "replace e with (a-2)<BR>\n" );
document.write( "2a + a - 2 = 25<BR>\n" );
document.write( "3a = 25 + 2<BR>\n" );
document.write( "3a = 27<BR>\n" );
document.write( "a = 27/3<BR>\n" );
document.write( "a = 9<BR>\n" );
document.write( "Now we know: 9 b c 2 e 3<BR>\n" );
document.write( "find e using e = a - 2<BR>\n" );
document.write( "e = 9 - 2<BR>\n" );
document.write( "e = 7<BR>\n" );
document.write( "find c using c = a - 1<BR>\n" );
document.write( "c = 9 - 1<BR>\n" );
document.write( "c = 8<BR>\n" );
document.write( "Find b using the total being 30<BR>\n" );
document.write( "9 + b + 8 + 2 + 7 + 3 = 30<BR>\n" );
document.write( "b + 29 = 30<BR>\n" );
document.write( "b = 1<BR>\n" );
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document.write( "Our number then: 9 1 8 2 7 3  </SPAN>\n" );
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