document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=944088>Question 944088</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve for this The sides of a square are altered so that one is increased by 3 and the other is decreased by 1. The area of the new shape is 32 ft2. What was the area of the original square? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #575623 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=575623\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> please help me solve for this The sides of a square are altered so that one is increased by 3 and the other is decreased by 1. The area of the new shape is 32 ft2. What was the area of the original square?<BR>\n" );
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document.write( "Original dimensions of the square:: x by x<BR>\n" );
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document.write( "Equation::<BR>\n" );
document.write( "(x+3)(x-1) = 32<BR>\n" );
document.write( "x^2 + 2x -3 = 32<BR>\n" );
document.write( "x^2 + 2x - 35 = 0<BR>\n" );
document.write( "Factor:<BR>\n" );
document.write( "(x+7)(x-5) = 0<BR>\n" );
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document.write( "Positive solution::<BR>\n" );
document.write( "x = 5<BR>\n" );
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document.write( "Ans: Original dimensions:: 5 ft by 5ft<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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