document.write( "Question 943982: car a and car b are 100 kms apart from each other travelling at different speeds. if they travel in same direction they meet after 5 hrs and if they tavel towards each other they meet in 1 hour.. find the speed of both cars \n" ); document.write( "
Algebra.Com's Answer #575614 by ankor@dixie-net.com(22740)\"\" \"About 
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car a and car b are 100 kms apart from each other travelling at different speeds.
\n" ); document.write( " if they travel in same direction, they meet after 5 hrs and
\n" ); document.write( " if they travel towards each other they meet in 1 hour..
\n" ); document.write( " find the speed of both cars
\n" ); document.write( ":
\n" ); document.write( "let a = car A's speed
\n" ); document.write( "let b = car B's speed
\n" ); document.write( "Then
\n" ); document.write( "(a + b) = their relative speed going towards each other
\n" ); document.write( "and
\n" ); document.write( "(a-b) = their relative speed going the same direction
\n" ); document.write( ":
\n" ); document.write( "Write distance equation for each scenario; dist = time * speed
\n" ); document.write( "5(a - b) = 100; going the same direction
\n" ); document.write( "1(a + b) = 100; going towards each other
\n" ); document.write( "We can simplify the 1st equation, divide both sides by 5, the 2nd equation can be left alone, we have then:
\n" ); document.write( "a - b = 20
\n" ); document.write( "a + b = 100
\n" ); document.write( "-------------Adding eliminates b, find a
\n" ); document.write( "2a = 120
\n" ); document.write( "a = 120/2
\n" ); document.write( "a = 60 mph the speed of A
\n" ); document.write( "Use the 2nd equation to find b, replace a with 60;
\n" ); document.write( "60 + b = 100
\n" ); document.write( "b = 100 - 60
\n" ); document.write( "b = 40 mph is the speed of B
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this in the 2nd equation, replacing a and b
\n" ); document.write( "5(60 - 40) = 100
\n" ); document.write( "5(20) = 100
\n" ); document.write( "
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