document.write( "Question 80220: If csc theta=-5/4 and theta is in quadrant 3,then cos theta= \n" ); document.write( "
Algebra.Com's Answer #57561 by stanbon(75887)\"\" \"About 
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If csc theta=-5/4 and theta is in quadrant 3,then cos theta=?
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\n" ); document.write( "Draw the picture of theta in the 3rd quadrant.
\n" ); document.write( "csc(theta)=r/y
\n" ); document.write( "The terminal side passes thru the point (x,-4) and r=5.
\n" ); document.write( "Find x where x^2+y^2=r^2
\n" ); document.write( "x^2=5^2-4^2=9
\n" ); document.write( "x=-3 in the 3rd Quadrant
\n" ); document.write( "Therefore cos(theta)= x/r=-3/5
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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