document.write( "Question 80220: If csc theta=-5/4 and theta is in quadrant 3,then cos theta= \n" ); document.write( "
Algebra.Com's Answer #57561 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! If csc theta=-5/4 and theta is in quadrant 3,then cos theta=? \n" ); document.write( "--------- \n" ); document.write( "Draw the picture of theta in the 3rd quadrant. \n" ); document.write( "csc(theta)=r/y \n" ); document.write( "The terminal side passes thru the point (x,-4) and r=5. \n" ); document.write( "Find x where x^2+y^2=r^2 \n" ); document.write( "x^2=5^2-4^2=9 \n" ); document.write( "x=-3 in the 3rd Quadrant \n" ); document.write( "Therefore cos(theta)= x/r=-3/5 \n" ); document.write( "========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |