document.write( "Question 944015: Express the following in index form
\n" ); document.write( "Logx + logy =1
\n" ); document.write( "Logx =6
\n" ); document.write( "Log (x+4) = log64
\n" ); document.write( "Log (2x+1) - log (3x-2)
\n" ); document.write( "Log (3x-1) - log2 = 3 \n" ); document.write( "

Algebra.Com's Answer #575606 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
Express the following in index form
\n" ); document.write( " Logx + logy =1
\n" ); document.write( "log(xy) = 1
\n" ); document.write( "xy = 10
\n" ); document.write( "-------------------
\n" ); document.write( " Logx =6
\n" ); document.write( "x = 10^6 = 1000000
\n" ); document.write( "--------------------------
\n" ); document.write( " Log (x+4) = log64
\n" ); document.write( "log(x+4)/(64) = 0
\n" ); document.write( "(x+4)/64 = 1
\n" ); document.write( "x+4 = 64
\n" ); document.write( "x = 60
\n" ); document.write( "------------------
\n" ); document.write( " Log (2x+1) - log (3x-2)
\n" ); document.write( "---
\n" ); document.write( "= log[(2x+1)/(3x-2)]
\n" ); document.write( "=======================\r
\n" ); document.write( "\n" ); document.write( " Log (3x-1) - log2 = 3
\n" ); document.write( "----
\n" ); document.write( "log[(3x-1)/2] = 3
\n" ); document.write( "----
\n" ); document.write( "(3x-1)/2 = 10^3
\n" ); document.write( "-----
\n" ); document.write( "3x-1 = 2000
\n" ); document.write( "3x = 2001
\n" ); document.write( "x = 667
\n" ); document.write( "----------------
\n" ); document.write( "cheers,
\n" ); document.write( "Stan H.
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