document.write( "Question 10974: In any triangle, the sum of the measures of the angles is 180 degrees. In triangle ABC, angle A is 4 times as large as angle B. Angle C measures 20 degrees less than angle B. Find the measure of each angle. \n" ); document.write( "
Algebra.Com's Answer #5756 by MArk_HeRras(6)\"\" \"About 
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A/R(representing the unknown):
\n" ); document.write( "4x = Angle A
\n" ); document.write( "x = Angle B
\n" ); document.write( "x-20 = Angle c\r
\n" ); document.write( "\n" ); document.write( "E(Equation): 4x + x + x - 20=180\r
\n" ); document.write( "\n" ); document.write( "S(Solution): \r
\n" ); document.write( "\n" ); document.write( "4x + x + 20 - x = 180\r
\n" ); document.write( "\n" ); document.write( "Add 4x + x - x = 4x\r
\n" ); document.write( "\n" ); document.write( "Then, transposed -20 to the right side showing us\r
\n" ); document.write( "\n" ); document.write( "180 - 20 = 160\r
\n" ); document.write( "\n" ); document.write( " 4x = 160\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now, Divide 4 to both sides like this:\r
\n" ); document.write( "\n" ); document.write( "4x/4 = 160/4\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The Answer is x = 40
\n" ); document.write( "C(Checking): 4(40) = 160 =Angle A
\n" ); document.write( " x = 40 = Angle B
\n" ); document.write( " 20 - 40 = -20\r
\n" ); document.write( "\n" ); document.write( "4(40) + 40 + 20 - 40 = 180
\n" ); document.write( "160 + 60 - 40 =180
\n" ); document.write( "220 - 40 = 180
\n" ); document.write( "180 = 180
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