document.write( "Question 943979: The length of a rectangle is 2 times longer than its width. If the diagonal of the rectangle measures 21 inches, what is its length?
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Algebra.Com's Answer #575562 by macston(5194) $\"\"$ $\"About$

You can put this solution on YOUR website!
the diagonal of the rectangle forms a right triangle with length and width as legs
\n" ); document.write( "so L^2+W^2=diagonal^2
\n" ); document.write( "W=width; L=length=2W; Diagonal=d=21 inches
\n" ); document.write( "Substitute for L:
\n" ); document.write( " $\"%282W%29%5E2%2BW%5E2=d%5E2\"$
\n" ); document.write( " $\"4W%5E2%2BW%5E2=%2821%29%5E2\"$
\n" ); document.write( " $\"5W%5E2=441\"$
\n" ); document.write( " $\"W%5E2=441%2F5\"$
\n" ); document.write( " $\"W=sqrt%28441%2F5%29\"$
\n" ); document.write( " $\"L=2W=2%2Asqrt%28441%2F5%29\"$ = $\"42%2Fsqrt%285%29\"$ ANSWER\r
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