document.write( "Question 80212: Find the half-life of a radioactive element that decays according to the rule:
\n" ); document.write( "dA/dt=-0.014A
\n" ); document.write( "where A is the amount in kg present after t years.
\n" ); document.write( "

Algebra.Com's Answer #57551 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Find the half-life of a radioactive element that decays according to the rule:
\n" ); document.write( "dA/dt=-0.014A
\n" ); document.write( "where A is the amount in kg present after t years.
\n" ); document.write( "--------
\n" ); document.write( "Integrating you get A(t)=-0.014At
\n" ); document.write( "If A is doubled you have:
\n" ); document.write( "2A=-0.014At
\n" ); document.write( "2=-0.014t
\n" ); document.write( "t=2/-0.014
\n" ); document.write( "---------
\n" ); document.write( "Comment:
\n" ); document.write( "This would give you a negative value for t.
\n" ); document.write( "I think something is missing in your posting.
\n" ); document.write( "Decay functions are exponential. Your posting
\n" ); document.write( "does not lead to that conclusion.
\n" ); document.write( "---------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );