document.write( "Question 943814: A regular polygon has 6 times as many diagonals as sides. How many sides does this polygon
\n" ); document.write( "have? How do you solve it,whats the strategy?
\n" ); document.write( "

Algebra.Com's Answer #575508 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "A regular polygon has 6 times as many diagonals as sides. How many sides does this polygon
\n" ); document.write( "have? How do you solve it,whats the strategy?
\n" ); document.write( "
No special strategy!! Just the use of the formula.
\n" ); document.write( "Formula for determining the number of diagonals of a polygon: \"n%28n+-+3%29%2F2\", with n being the number of sides
\n" ); document.write( "Since there are 6 times as many diagonals as numbers of sides, then number of diagonals = 6n
\n" ); document.write( "We now have: \"n%28n+-+3%29%2F2+=+6n\"
\n" ); document.write( "\"%28n%5E2+-+3n%29%2F2+=+6n\"
\n" ); document.write( "\"n%5E2+-+3n+=+12n\" ------ Cross-multiplying
\n" ); document.write( "\"n%5E2+-+3n+-+12n+=+0\"
\n" ); document.write( "\"n%5E2+-+15n+=+0\"
\n" ); document.write( "n(n - 15) = 0
\n" ); document.write( "Number of sides, or \"highlight_green%28n+=+15%29\" OR n = 0 (ignore) \n" ); document.write( "
\n" );