document.write( "Question 943816: In the triangle below, side BC is 12 units long and side AC is 15 units long. If angle < C is 60 degrees, then what is side AB-squared? \r
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document.write( "A. 64
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document.write( "B. 81
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document.write( "C. 189
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document.write( "D. 369
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document.write( "E. 549\r
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document.write( "I tried using the Rule of Cosines, but I'm not getting any of the answer choices.
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document.write( "I did: AB-squared = AC-squared + BC squared - 2(AC)(BC)cos60
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document.write( " (AB)^2 = (15)^2 + (12)^2 - 2(15)(12)cos60
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document.write( " For (AB)^2 = 711.8686 \n" );
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Algebra.Com's Answer #575483 by MathLover1(20849)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "if \n" ); document.write( "\n" ); document.write( "pay attention to the question: what is side \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, your answer is: C. \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |