document.write( "Question 943816: In the triangle below, side BC is 12 units long and side AC is 15 units long. If angle < C is 60 degrees, then what is side AB-squared? \r
\n" ); document.write( "\n" ); document.write( "A. 64
\n" ); document.write( "B. 81
\n" ); document.write( "C. 189
\n" ); document.write( "D. 369
\n" ); document.write( "E. 549\r
\n" ); document.write( "\n" ); document.write( "I tried using the Rule of Cosines, but I'm not getting any of the answer choices.
\n" ); document.write( "I did: AB-squared = AC-squared + BC squared - 2(AC)(BC)cos60
\n" ); document.write( " (AB)^2 = (15)^2 + (12)^2 - 2(15)(12)cos60
\n" ); document.write( " For (AB)^2 = 711.8686
\n" ); document.write( "

Algebra.Com's Answer #575483 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "if \"BC=12\" units long, side \"AC=15\" units long, and angle < \"C+=60\" degrees, then we have\r
\n" ); document.write( "\n" ); document.write( "pay attention to the question: what is side \"AB-squared\"?\r
\n" ); document.write( "\n" ); document.write( "\"%28AB%29%5E2+=+15%5E2+%2B+12%5E2+-+2%2815%29%2812%29cos%2860%29\".....\"cos%2860%29=1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28AB%29%5E2+=+225+%2B+144+-+360%2A%281%2F2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28AB%29%5E2+=+369+-+180\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28AB%29%5E2+=+189\" => this is \"AB-squared\"\r
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\n" ); document.write( "\n" ); document.write( "so, your answer is: C. \"189\"\r
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