document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=943775>Question 943775</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you find degree y of a right triangle whose hypotenuse is n (square root 5), adjacent is 2n and opposite side is n. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #575450 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=575450\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> your angle is 26.56505118 degrees.\r<BR>\n" );
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document.write( "you get sin(y) = n / n*sqrt(5) which is equal to 1/sqrt(5)\r<BR>\n" );
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document.write( "you get cos(y) = 2n / n*sqrt(5) which is equal to 2/sqrt(5)\r<BR>\n" );
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document.write( "you get tan(y) = n / 2n = 1/2\r<BR>\n" );
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document.write( "use your calculator to get arcsin and arccos and arctan and they all point to 26.56505118 degrees.\r<BR>\n" );
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