document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=943832>Question 943832</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What number can be inserted in the blank space so that 59_172 is divisible by 6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #575447 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=575447\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the first 2 digits can't change.<BR>\n" );
document.write( "59/6 = 9 with a remainder of 5.<BR>\n" );
document.write( "the problem reduces to 6 dividing evenly into 5_172<BR>\n" );
document.write( "the number can't be 4 because then 6 would divide evenly into 54 and 6 doesn't divide evenly into 172.<BR>\n" );
document.write( "since the number has to be the remainder of a division of 6 into 5_, then the number can't be greater than 5.<BR>\n" );
document.write( "that leave 1,2,3 and 5 as the possible numbers.<BR>\n" );
document.write( "it remains to test each one to see which one will allow the division to complete evenly.<BR>\n" );
document.write( "6 doesn't divide evenly into 51172<BR>\n" );
document.write( "nor 52172<BR>\n" );
document.write( "yes 53172<BR>\n" );
document.write( "the number has to be 3<BR>\n" );
document.write( "your number becomes 593172<BR>\n" );
document.write( "divide that by 6 and you get 98862<BR>\n" );
document.write( "the missing number has to be 3.<BR>\n" );
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