document.write( "Question 943808: Mica travel constant speed 3 hours. Then slowed speed for 11 miles. The entire trip took 6 hours and covered 375 miles. What was the speed on the turnpike? \n" ); document.write( "
Algebra.Com's Answer #575445 by ankor@dixie-net.com(22740)\"\" \"About 
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Mica travel constant speed 3 hours.
\n" ); document.write( " Then slowed his speed by 11 mph. (Changed the wording here to make sense.)
\n" ); document.write( " The entire trip took 6 hours and covered 375 miles.
\n" ); document.write( " What was the speed on the turnpike?
\n" ); document.write( ":
\n" ); document.write( "Let s = the speed on the turn-pike
\n" ); document.write( "then
\n" ); document.write( "3s = his distance at turn-pike speed
\n" ); document.write( "the total time was 6 hr, therefore:
\n" ); document.write( "3(s-11) = distance at the slower speed
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation; dist = speed * time
\n" ); document.write( "3s + 3(s-11) = 375
\n" ); document.write( "3S + 3S - 33 = 375
\n" ); document.write( "6S = 375 + 33
\n" ); document.write( "6S = 408
\n" ); document.write( "S = 408/6
\n" ); document.write( "S = 68 mph on the turn-pike
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