document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=943557>Question 943557</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the area of a rectangle is 20 cm. and its length is 19 less than 6 times its width, what are the length and width? Can you show me how you got the answer? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #575373 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=575373\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Length = 5<BR>\n" );
document.write( "Width = 4 (to check, 5 = 6*4 - 19)\r<BR>\n" );
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document.write( "You can guess and check at the answer in some cases. A more algebraic solution is to let W be the width, then the length is 6W-19, and W(6W-19) = 20. This is equivalent to the quadratic 6W^2 - 19W - 20 = 0. Solve via factoring or quadratic formula. </SPAN>\n" );
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