Algebra.Com's Answer #575372 by MathTherapy(10552)  You can put this solution on YOUR website! Anne solved 5(2x)- 3 = 20x + 15 for x by first distributing 5 on the left side of the equation. She got the answer x = -3. However, when she substituted -3 into the original situation for x, she saw that her answer was wrong. What did Anne do wrong, and what is the correct way? \n" );
document.write( "She seemed to have distributed the 5 on the entire left side of the equation instead of only distributing \n" );
document.write( "the 5 to the 2x. This is what she might've done: \n" );
document.write( "5(2x - 3) = 20x + 15 \n" );
document.write( "10x - 15 = 20x + 15 \n" );
document.write( "10x - 20x = 15 + 15 \n" );
document.write( "- 10x = 30 \n" );
document.write( " , or \r \n" );
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document.write( "Correct solution, since she was wrong, as well as the person who responded: \n" );
document.write( "5(2x) - 3 = 20x + 15 \n" );
document.write( "10x - 3 = 20x + 15 \n" );
document.write( "10x - 20x = 15 + 3 \n" );
document.write( "- 10x = 18 \n" );
document.write( " , or , or \n" );
document.write( "You can do the check!! \n" );
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