document.write( "Question 80193: n-5 1 n-3
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document.write( "---- = --- - ----
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document.write( "6n-6 9 4n-4\r
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document.write( "I tried to my best to type the fractions so I hope this makes sense. Can you help me solve this? \n" );
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Algebra.Com's Answer #57535 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! n-5 1 n-3 \n" ); document.write( "---- = --- - ---- \n" ); document.write( "6n-6 9 4n-4 \n" ); document.write( ": \n" ); document.write( "Assume you mean: \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Factor out what you can in the denominator \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "6, 4, 9 are all factors of 36, our common denominator is 36(n-1) \n" ); document.write( "Multiplying each term will get rid of the denominator, we then have: \n" ); document.write( ": \n" ); document.write( "6(n-5) = 4(n-1) - 9(n-3) \n" ); document.write( ": \n" ); document.write( "6n - 30 = (4n - 4) - (9n - 27) \n" ); document.write( ": \n" ); document.write( "6n - 30 = 4n - 4 - 9n + 27 \n" ); document.write( ": \n" ); document.write( "6n -30 = -5n + 23 \n" ); document.write( ": \n" ); document.write( "6n + 5n = 23 + 30 \n" ); document.write( ": \n" ); document.write( "11n = 53 \n" ); document.write( ": \n" ); document.write( "n = 53/11 \n" ); document.write( ": \n" ); document.write( "n ~ 4.8, I used this to check for equality and it checked out \n" ); document.write( " |