document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=80194>Question 80194</A>: <I><SPAN STYLE=\"word-break: break-all;\"> n-5/6n-6 = 1/9 - n-3/4n-4\r<BR>\n" );
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document.write( "I tried to my best to type the fractions so I hope this makes sense. Can you help me solve this?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #57533 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=57533\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> [(n-5)/(6n-6)] = 1/9 -[(n-3)/(4n-4)]<BR>\n" );
document.write( "[(n-5)/(6(n-1))] = 1/9 -[(n-3)/(4(n-1)]<BR>\n" );
document.write( "The least common multiple is (36(n-1))<BR>\n" );
document.write( "Multiply thru by the lcm to get:<BR>\n" );
document.write( "[6(n-5)] = 4(n-1) - [9(n-3)]<BR>\n" );
document.write( "6n-30-= 4n-4 -9n+27<BR>\n" );
document.write( "6n-30 = -5n+23<BR>\n" );
document.write( "11n=53<BR>\n" );
document.write( "n=53/11<BR>\n" );
document.write( "==============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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