document.write( "Question 80192: If the discriminat is negative, would this be a true statement? \r
\n" ); document.write( "\n" ); document.write( "The discriminant is negative, so the quadratic has no real-valued zeroes and therefore no solution. \n" ); document.write( "
Algebra.Com's Answer #57524 by vertciel(183)\"\" \"About 
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Hello there,\r
\n" ); document.write( "\n" ); document.write( "In quadratic equations, if the discriminant (Δ = b^2 - 4ac) is:\r
\n" ); document.write( "\n" ); document.write( "Δ > 0 - This quadratic will have 2 roots, otherwise known as x intercepts.\r
\n" ); document.write( "\n" ); document.write( "Δ = 0 - This quadratic will have a double root. That is, both roots will be the same, thus, you get the x co-ordinate of the vertex.\r
\n" ); document.write( "\n" ); document.write( "Δ < 0 - You will not get a real solution, but a complex solution. If you have not covered complex numbers yet, then just understand that there will be no x-intercepts since the quadratic does not touch the x axis. \r
\n" ); document.write( "\n" ); document.write( "Now, if your discriminant is negative, under which of the three cases will negative discriminants fall?\r
\n" ); document.write( "\n" ); document.write( "Be sure to write back if you need more help.\r
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